A new December and a new bunch of puzzles from mscroggs.co.uk.

The 2 3-digit numbers will be axb and cxd. We want a*x*b = c*x*d, and 99 < axb < cxd. Then the answer is axb.

a*x*b = c*x*d <=>

a*b = c*d

These 4 digits are all different. A possible solution is 1*6 = 2*3 = 6. Then a would be as small as possible, 1. And 6 is the smallest number, that can be factorized in 2 very different ways. So my guess is axb = 1×6.

For x just choose the smallest digit available, 4.

axb = 146.

When I got a hint, that this answer was wrong, I looked at it again. We get something smaller, if x is smaller than 4. This is possible for x = 3, axb = 138, cxd = 234 or 432.